0/5
## Uniswap V2 Arbitrage Optimal Amount In In this lesson, we will derive the optimal amount of a token to put in to Uniswap V2 contracts to maximize an arbitrage opportunity. We will start with two Uniswap V2 AMMs: AMMA and AMMB. We will assume that both AMMs are selling the same tokens. We will also assume that the price of the token on AMMA is cheaper than the price of the token on AMMB. We will use this opportunity to buy the token on AMMA, where it is cheaper, and sell it on AMMB, where it is more expensive. This will bring the prices closer together and result in a profit. We will define the following variables to derive the optimal amount of token to put in: * F = swap fee. We will assume that the swap fee is the same on both AMMs. The swap fee will be a number between 0 and 1. * X_A = AMMA reserve out. The reserve out is the amount of the token that is coming out of the AMM. * Y_A = AMMA reserve in. The reserve in is the amount of the token that is going into the AMM. * X_B = AMMB reserve in. * Y_B = AMMB reserve out. We will then use these variables to calculate the profit from the arbitrage. We will define the profit from the arbitrage as F(dy_a), where dy_a is the amount of token y that we put into AMMA. F(dy_a) is equal to dy_b - dy_a, where dy_b is the amount of token y that we get out of AMMB. We want to find the dy_a that maximizes F(dy_a). We will use calculus to find this value. We will first find the derivative of F(dy_a) with respect to dy_a. F'(dy_a) = dy_b'-1 We then need to find where F'(dy_a) = 0, and this will be the dy_a that maximizes F(dy_a). To find where F'(dy_a) = 0, we can use the quadratic formula. The quadratic formula is: ``` dy_a* = (-b + sqrt(b^2 - 4ac)) / 2a ``` Where a, b, and c are defined as follows: * a = k^2 * b = 2 * k * x_a * y_b * c = (y_a * x_b) + ( (1 - f) * x_b + (1 - f)^2 * x_a )^2 Plugging these values into the quadratic formula will give us the optimal amount of token y to put into AMMA to maximize the arbitrage profit. We will derive the quadratic formula for a, b, and c in the next lesson.
A comprehensive guide to calculating optimal amount in for Uniswap V2 arbitrage. This lesson explains how to determine the optimal amount of tokens to input in order to maximize profit when arbitraging between two Uniswap V2 pools.
Previous lesson
Previous
Give us feedback
Course Overview
About the course
How to use Uniswap v2 dex and contracts
Interacting with the Uniswap v2 router and factory
How to create Uniswap v2 liquidity pools
How to add liquidity to Uniswap v2 pools
Swaps, flash swaps, flash swap arbitrage, and time-weighted average price (TWAP)
Security researcher
$49,999 - $120,000 (avg. salary)
Smart Contract Auditor
$100,000 - $200,000 (avg. salary)
Smart Contract Engineer
$100,000 - $150,000 (avg. salary)
Web3 developer
$60,000 - $150,000 (avg. salary)
Web3 Developer Relations
$85,000 - $125,000 (avg. salary)
Last updated on October 9, 2024
Solidity Developer
Uniswap V2Duration: 14min
Duration: 1h 20min
Duration: 10min
Duration: 54min
Duration: 25min
Duration: 26min
Duration: 1h 03min
Duration: 59min
Course Overview
About the course
How to use Uniswap v2 dex and contracts
Interacting with the Uniswap v2 router and factory
How to create Uniswap v2 liquidity pools
How to add liquidity to Uniswap v2 pools
Swaps, flash swaps, flash swap arbitrage, and time-weighted average price (TWAP)
Security researcher
$49,999 - $120,000 (avg. salary)
Smart Contract Auditor
$100,000 - $200,000 (avg. salary)
Smart Contract Engineer
$100,000 - $150,000 (avg. salary)
Web3 developer
$60,000 - $150,000 (avg. salary)
Web3 Developer Relations
$85,000 - $125,000 (avg. salary)
Last updated on October 9, 2024
Testimonials
Read what our students have to say about this course.
Chainlink
Chainlink
Gustavo Gonzalez
Solutions Engineer at OpenZeppelin
Francesco Andreoli
Lead Devrel at Metamask
Albert Hu
DeForm Founding Engineer
Radek
Senior Developer Advocate at Ceramic
Boidushya
WalletConnect
Idris
Developer Relations Engineer at Axelar